solution manual computer system architecture by M. MORRIS MANO

By M. MORRIS MANO

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9 - 36 - Loc 10B 10C 10D 10E 10F Hex 0150 0000 FF9C 0000 0000 150 : 004B : 1B3 0017 . ADS, PTR, NBR, CTR, SJH, HEX 150 HEX 0 DEC-100 HEX 0 HEX 0 ORG 150 DEC 150 : . 10 (a) MRI Table Memory Symbol HEX word 41 4D ⎡1 A N ⎢ 2 D Space 44 20 ⎢ AND ⎢⎣3 value 00 00 41 44 ⎡4 A D ⎢ ADD 5 D space 44 20 ⎢ ⎢⎣ 6 value 10 00 etc. (b) non - MRI Table Memory Symbol HEX word 43 4C ⎡1 C L ⎢ CLA 2 A Space 41 20 ⎢ ⎢⎣3 value 78 00 43 4C ⎡4 C L ⎢ CLE 5 E space 45 20 ⎢ ⎢⎣ 6 value 74 00 etc. 12 (a) B A N10 N30 N20 /Form A-B /skip if AC positive /(A–B) < 0, go to N 10 /skip if AC = 0 /(A–B) > 0, go to N30 /(A–B) = 0, go to N20 The program counts the number of 1’s in the number stored in location WRD.

Store M[314] ← R3 1 FI FI 2 DA FI 3 FO DA FI 4th step EX FO DA FI Segment EX: transfer memory word to R1. Segment FO: Read M[313]. Segment DA: Decode (increment) instruction. Segment FI: Fetch (the store) instruction from memory. 13 Insert a No-op instruction between the two instructions in the example of Problem 9-12 (above). 15 Add R2 to R3 Branch to 104 Increment R1 Store R1 1 I I Use example of Problem 9-14. 16 (a) There are 40 product terms in each inner product, 402 = 1,600 inner products must be evaluated, one for each element of the product matrix.

11 1. Load R1 ← M [312] 2. Add R2 ← R2 + M [313] 3. Increment R3 4. Store M[314] ← R3 1 FI FI 2 DA FI 3 FO DA FI 4th step EX FO DA FI Segment EX: transfer memory word to R1. Segment FO: Read M[313]. Segment DA: Decode (increment) instruction. Segment FI: Fetch (the store) instruction from memory. 13 Insert a No-op instruction between the two instructions in the example of Problem 9-12 (above). 15 Add R2 to R3 Branch to 104 Increment R1 Store R1 1 I I Use example of Problem 9-14. 16 (a) There are 40 product terms in each inner product, 402 = 1,600 inner products must be evaluated, one for each element of the product matrix.

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