By R. G. Compton
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The repulsion in the exit channel disposes essentially all the potential energy associated with the high exit barrier (see Fig. 18) into translational motion of the products and, therefore, only 36% of the available energy goes in internal degrees of freedom. 6 Â , which corresponds to a maximum initial orbital angular momentum L m a x~94fi. 8 kcal/mol, that is about 25% of the total available energy. This result leaves only 11% of the total available energy which can be carried away in vibrational degrees of freedom, with the conclusion that essentially only the CO2 bending (010) can be excited, with the symmetric stretch (100) and two quanta of bending (020) being barely accessible.
15, together with the most probable Newton diagram. The lab angle Θ is measured from the OH beam. ) coordinate system, û=0° is the direction of the OH beam and represents the forward direction with respect to OH. The circle in the Newton diagram (see Fig. 15) represents the maximum cm. speed for HOD product assuming that the OH reactant is in v=0 and that all the available energy goes into product translational energy. The HOD angular distribution peaks sharply to the right of the cm. angle, indicating that the product is thoroughly backscattered.
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