# Matrix Groups: An Introduction to Lie Group Theory (Springer by Andrew Baker By Andrew Baker

In the course of the textual content, the emphasis is on delivering an process that's obtainable to readers outfitted with a customary undergraduate toolkit of algebra and research. even if the formal necessities are stored as low point as attainable, the subject material is refined and comprises some of the key subject matters of the absolutely built concept, getting ready scholars for a extra commonplace and summary path in Lie idea and differential geometry.

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For property 2, if KIF is purely inseparable, then each min(F, a) splits over K, since the only root of min( F, a) is a itself. 28. If (J E Gal(KI F), then, for any a E K, the automorphism (J maps a to a root of min(F, a). Thus, (J(a) = a, so (J = id. Therefore, Gal(KI F) = {id}. If [K : F] < 00, then I{ is finitely generated over Fj say, K = F(al,' .. 20 it suffices by illdlldioll U) prove this ill the case K = F(a). But then [K : F] = deg(min(F,a)), which is a power of p by the previous lemma.

This Galois group is Abelian and is isomorphic to 7l/271 x 'lL/271. The subgroups of C = Gal(K/Q) are (id) , (CJ) , (T) , (CJT) ,C. w w -+ -+ w, w2 . (Y6) , «J!. TCJ. The (id) , (CJ) , (T) , (o"T) , (0"2T) ,G. (\;/2), Q(w 2 \Y2), Q(w\;/2), Q. One way to verify that these 'fields are in fact the correct ones is to show that, for any of these fields, the field is indeed fixed by the appropriate subgroup and its dimension over «J! is correct. ( ij2) ~ F(T). Since the index [G : (T)] = 3, we must have (F(Y) : F] = 3.

Proof. This corollary follows immediately from the preccding corollary since any finite extension of a field of characteristic 0 is separable. 0 The normal closure of a field extension Let K be an algebraic extension of F. The normal closure of Kj F is the splitting field over F of the set {min(F, a) : a E I(} of minimal polynomials of clements of IC As we will show below, the llormal closnre N of the extension J( j F is a llliuilllalnol"lllal extellsion of jI' which contains J(. This is reasonable since, for each a E 1<, the polynomial min(F, a) splits over any normal extension of F containing K.