Certified Programs and Proofs: Third International by Daniel R. Licata, Guillaume Brunerie (auth.), Georges

By Daniel R. Licata, Guillaume Brunerie (auth.), Georges Gonthier, Michael Norrish (eds.)

This publication constitutes the refereed court cases of the 3rd foreign convention on qualified courses and Proofs, CPP 2013, colocated with APLAS 2013 held in Melbourne, Australia, in December 2013. The 18 revised ordinary papers provided including 1 invited lecture have been conscientiously reviewed and chosen from 39 submissions. The papers are prepared in topical sections on code verification, stylish proofs, evidence libraries, qualified adjustments and security.

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Extra resources for Certified Programs and Proofs: Third International Conference, CPP 2013, Melbourne, VIC, Australia, December 11-13, 2013, Proceedings

Sample text

Chlipala’s Bedrock project [9] also aims to decrease the tedium of separation logic proofs in Coq, with a focus on tactical- and reflection-based automation of proofs about low level programs. Bengtson operates on a Java-like language and Chlipala uses a simple but expressive low-level continuation-based language. Earlier versions of our work (Appel [1]) used a number of tactics to automate proofs as well. In this system, the user was left with the burden of completing proofs of expression evaluation.

Once we have encoded the negation of the initial implication P =⇒ wp pg Q, together with the background theory th, as a set of clauses (its so-called clausal normal form) we simplify the resulting clause set to remove tautologous and otherwise redundant clauses, then begin searching for a contradiction by iterating the following procedure. 967 968 969 970 971 972 973 974 975 976 Definition step (act pas: list clause): result := match pas with | nil => if invert act then Unsat else Sat act | nil :: pas’ => Unsat | given :: pas’ => let act’ := given::act in let resolvents := map condense (resolve given act’ nil) in let resolvents’ := filter (negb ◦ subsumedBy pas) resolvents in Later act’ (pas’ ++ resolvents’) end.

Thus, the user can think about values, not about evaluation, just as in a paper proof. repr 3)) All we are left with is the case that the division doesn’t overflow. The other conditions (c is initialized, 3 = 0 ) have computed to True and simplified away. We can no longer see the variables -c and -a. Now we can apply some simple Boolean rewrite rules with solve-tc and solve the goal. Not all typechecker-introduced assertions will be so easy to solve, of course; in place of solve-tc the user might have to do some real work.

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